Conservation of angular momentum?

Maritza Ebanks: Let L = angular momentum = I*omega where i = moment of inertia and omega = angular velocitynow omega = v/r and I = 1/2*m*r^2 (for a solid disk) for a hoop use m*r^2 (but for conservation in this problem it really doesn't)So L = 1/2*m*r1^2*(v1/r1) = 1/2*m*r2^2*(v2/r2) Simplifying we getr1*v1 = r2*v2 If you had used m*r^2 for I you would have obtained the same results...Show more

Rosio Pasculli: L = IωI = mr^2 for a hoop; it's mr^2/2 for a uniform disc, but it won't matter here because you only care about proportions for your question.ω = v/rL = (mr^2)(v/r)L = mvrSo if mass stays constant,m(v1)(r1) = m(v2)(r2) = I(v1)(r1) = (v2)(r2) = I/m...Show more

Ignacio Imbier: Every derivative of mass with respect to motion has an effect on the magnitude and/or direction of the local gravitational field. Even things like compression and shear stress do this a bit. The mass-energy contribution to the gravitational field is the only contribution th! at's large enough for us to notice most of the time (the DC component, you might say). So angular momentum is a minor source of gravity, which causes gravity to be less than entirely a central force.